1=-(-2)^2+b

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Solution for 1=-(-2)^2+b equation: 



1=-(-2)^2+b

We move all terms to the left:

1-(-(-2)^2+b)=0



We calculate terms in parentheses: -(-(-2)^2+b), so:

-(-2)^2+b

determiningTheFunctionDomain
b-(-2)^2

We add all the numbers together, and all the variables

b-4

Back to the equation:

-(b-4)



We get rid of parentheses

-b+4+1=0

We add all the numbers together, and all the variables

-1b+5=0

We move all terms containing b to the left, all other terms to the right

-b=-5

b=-5/-1

b=+5

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